If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x^2 = 0
x^2 = 0
x^2 = 0
1*x^2 = 0 // : 1
x^2 = 0
x = 0
x in (-oo:0) U (0:+oo)
25*x^2-(4/(x^2))-9 = 0
25*x^2-4*x^-2-9 = 0
t_1 = x^2
25*t_1^1-4*t_1^-1-9 = 0
25*t_1^1-4*t_1^-1-9*t_1^0 = 0
(25*t_1^2-9*t_1^1-4*t_1^0)/(t_1^1) = 0 // * t_1^2
t_1^1*(25*t_1^2-9*t_1^1-4*t_1^0) = 0
t_1^1
25*t_1^2-9*t_1-4 = 0
25*t_1^2-9*t_1-4 = 0
DELTA = (-9)^2-(-4*4*25)
DELTA = 481
DELTA > 0
t_1 = (481^(1/2)+9)/(2*25) or t_1 = (9-481^(1/2))/(2*25)
t_1 = (481^(1/2)+9)/50 or t_1 = (9-481^(1/2))/50
t_1 in { (9-481^(1/2))/50, (481^(1/2)+9)/50}
t_1 = (9-481^(1/2))/50
x^2-((9-481^(1/2))/50) = 0
1*x^2 = (9-481^(1/2))/50 // : 1
x^2 = (9-481^(1/2))/50
t_1 = (481^(1/2)+9)/50
x^2-((481^(1/2)+9)/50) = 0
1*x^2 = (481^(1/2)+9)/50 // : 1
x^2 = (481^(1/2)+9)/50
x^2 = (481^(1/2)+9)/50 // ^ 1/2
abs(x) = ((481^(1/2)+9)^(1/2))/(5*2^(1/2))
x = ((481^(1/2)+9)^(1/2))/(5*2^(1/2)) or x = -(((481^(1/2)+9)^(1/2))/(5*2^(1/2)))
x in { ((481^(1/2)+9)^(1/2))/(5*2^(1/2)), -(((481^(1/2)+9)^(1/2))/(5*2^(1/2))) }
| y+5=2(x+5) | | X^2-12x=21 | | (6x+50)=146 | | y+10=2(x+5) | | K-50=137 | | 2*12/-15 | | 42*6= | | h/(0.3*4)=5 | | x+2/x^3 | | 5x+10/x^8 | | x/4+22=34 | | 3x/16y^9 | | 9x^5/8y^2 | | x^2+681=62x+9 | | (16/9)^(-3/2) | | 2x^2=15x-27 | | 4(x-6)-3(x+5)=2(x+3)+2(x-6) | | 9/5x+5/6=4/5x+1/2 | | 31x-35x-6x= | | 2/3x-10+8 | | c^3+8/c^5-4c^3 | | -12=-16t^2+80t+4 | | (-1)+(38)= | | 0.30x+0.60(30)=0.15(102) | | 55-7x=11x+17 | | 125-4x=23x+20 | | 11+10(p+10)=(2p+11) | | 55-7x=11x | | 7y-34+9y=16(y-2) | | -x+0=10 | | 2x+28=4/9x | | 7a-14/4-a^2 |